"She Wants a Man, Not a Boy"

You asked her if she wanted to grab coffee. Then you asked if the time worked. Then you asked if the place was okay. Then you asked if she'd prefer tea.

Four questions. Four chances for her to say no. Four signals that you're terrified of making a decision.

Plan it. Pick the place. Pick the time. Tell her where to meet you. She'll either show up or she won't.

Either way, you look like a man instead of a scared little boy.

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help with basic EE question

K

kickureface

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having some trouble with this one-
signal travels via optical fiber from LA to chicago 3000km away. the signal is 10^6 bytes at 10^8 bits/sec
a. how long is the signal in seconds.
b. if the first signal bit leaves LA at t=0, when does it reach chicago?
c. when does the last signal reach chicago

part a is simple, some division and unit conversion
part b and c throw me off-am i suposed to know how fast signal bits are? and how much separation is between the first and last bits?
 

"You Can't Argue a Woman Into Liking You"

You made your case like a lawyer. Stable job. Good guy. Ready for something real. All true. All irrelevant.

She weighed your points, nodded along, felt nothing — then fell hard for some tattooed bartender with a motorcycle and a gambling problem.

Logic is where attraction goes to die. The "22 Rules" work a level deeper, on the subconscious switches that decide within minutes whether you register as a MAN or as part of the furniture.

Stop presenting evidence. Start flipping switches.

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Phyzzle

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I hope you're in High School and not College, heh.

am i suposed to know how fast signal bits are?
Click to expand...
Well, the signal bits are light . . . so how fast is light? Are you given the refractive index of fiber-optic glass anywhere?
 
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Mr. Wolf

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a. (10^6 * 8) / 10^8 = (10^14) / 10^8 = 10^6 = sL - signal length in seconds.

b. t_chicago = 1/(3000km / c) + t + k

where c is speed of light in km per seconds.. k is some sort of constant that slows light down as it travels.

c. t_chicago seconds + sL
 
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