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Cant get this fugging Problem right.

L

Lost

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Well ive been trying to plug this algebra problem in for hours.
College Algebra... we have to use this thing online called ILRN to do our homework. So we HAVE to get it 100 percent right or it doesnt accept.

Well im pretty ****ing sure im doing it right. but it keeps saying wrong when i put the answer in, someone please help!! here is the problem:

Use your calculator to find the minimum value of the quadratic function below, correct to two decimal places.

f (x) = x 2 + 6.45x + 5.93

Enter your answer in the form f (a) = b.



I got x=-3.191489 and y=-4.469502 for the minimum


HELP!!
 
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Centaurion

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the min is x = -3.224992 y = -4.470625

and max = infinity

i'll let you do the rounding, cause you know how to do that, right..?

i dont want to sounds like an ass, but it took me like 5seconds to find that one out with my calc.
 
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Lost

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I know what it is. It says its wrong tho. ****

btw every time i get on it puts different #'s so its the same type of problem just differnt #'s cuz it thinks im starting over
This has nothing to do with it tho.. everytime i use the same procedure but it says its wrong, WTF!!!

and i ****ing know how to do it. dont drill me on "oh it took 5 seconds" . it TOOK ME THE SAME. but it says its wrong
 
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Centaurion

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lol

Do they give you a range for x? Are they asking for local min within that range or abosolute min?

if not, x = -3.22 is y = -4.47 is CORRECT. Email whoever is reposible for that **** and tell them about your problem.
 
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sorry if i sounded like n ass yesterday


I was kinda (understatement) pissed.

I guess you would be too if you plugged in an answer for a math problem for 5 hours and it kept saying WRONG in Red :eek:
 
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Luscious

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Next time you need the max/min of a function, and you can't get it on your calculator...(this is the process as far as I recall, last math class was about a year ago)

Take derivative, reduce the derivative into brackets, set it equal to zero. Find the values of x that will make each bracket equal to zero (one or more values). Evaluate the original expression at said x-values, and also the maximum and minimum x-values of the interval you're interested in.

Rather drawn-out, but hey, it'll help if you screw up your calculator on a test.
 
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